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60x^2-300x-3000=0
a = 60; b = -300; c = -3000;
Δ = b2-4ac
Δ = -3002-4·60·(-3000)
Δ = 810000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{810000}=900$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-300)-900}{2*60}=\frac{-600}{120} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-300)+900}{2*60}=\frac{1200}{120} =10 $
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